Academic Recap

100 mL 0.1 M Na₂CO₃ দ্রবণ তৈরী করতে কতটুকু Na₂CO₃ প্রয়োজন?

A
1.06 g
B
1.22 g
C
1.57 g
D
1.84 g
Medical Admission

ব্যাখ্যা (Explanation):

C = n / V(L) => C = (W/M) / V(L) => W = C × M × V(L) = 0.1 × 106 × 0.1 = 1.06 g।

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